ผลต่างระหว่างรุ่นของ "Probstat/notes/balls and bins"
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Jittat (คุย | มีส่วนร่วม) |
Jittat (คุย | มีส่วนร่วม) |
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แถว 14: | แถว 14: | ||
Let random variable ''X'' be the number of empty bins. | Let random variable ''X'' be the number of empty bins. | ||
− | '''Question 1:''' ''What is P{ X'' = 0 }?'' | + | {{กล่องฟ้า|'''Question 1:''' ''What is P{ X'' = 0 }?'' |
If there is no empty bin, every ball must land into different bin. In this case, the first ball has n choices, the second ball has n-1 choices, and in general the ''i''-th ball has ''n - i +1'' choices. Therefore, there are <math>n\cdot (n-1)\cdot(n-2)\cdots(2)(1) = n!</math> outcomes. The probability is <math>\frac{n!}{n^n}</math>. | If there is no empty bin, every ball must land into different bin. In this case, the first ball has n choices, the second ball has n-1 choices, and in general the ''i''-th ball has ''n - i +1'' choices. Therefore, there are <math>n\cdot (n-1)\cdot(n-2)\cdots(2)(1) = n!</math> outcomes. The probability is <math>\frac{n!}{n^n}</math>. | ||
+ | }} | ||
− | It will be very hard to compute E[''X''] directly. | + | It will be very hard to compute E[''X''] directly. (Just computing ''P''{ ''X'' = 3 } seems to be exceedingly hard.) |
== Fullest bins == | == Fullest bins == |
รุ่นแก้ไขเมื่อ 03:43, 18 กันยายน 2557
- This is part of probstat. The materials on this part is from this course at Berkeley.
We consider a balls-and-bins experiment where we throw n balls independently into n bins uniformly at random.
Question 1: How many possible outcomes are there?
Since each ball has n choices and their choices are independent, there are outcomes.
Question 2: What is the probability that bin 1 is empty?
In this case, each ball only have n - 1 choices (because they have to avoid bin 1); therefore there are outcomes where bin 1 is empty. Since each outcome is equally likely, the probability that bin 1 is empty is .
Number of empty bins
Let random variable X be the number of empty bins.
{{{1}}}
It will be very hard to compute E[X] directly. (Just computing P{ X = 3 } seems to be exceedingly hard.)