ผลต่างระหว่างรุ่นของ "01204212/friends"
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Jittat (คุย | มีส่วนร่วม) (→Code) |
Jittat (คุย | มีส่วนร่วม) (→Code) |
||
(ไม่แสดง 5 รุ่นระหว่างกลางโดยผู้ใช้คนเดียวกัน) | |||
แถว 1: | แถว 1: | ||
: ''This part of [[01204212]]'' | : ''This part of [[01204212]]'' | ||
+ | |||
+ | In this task you will work with graphs from real social networks. | ||
+ | |||
+ | * [http://theory.cpe.ku.ac.th/~jittat/courses/01204212/tasks/graph1/facebook.in facebook.in] -- This is a graph from facebook. It is an undirected graph. The graph is from [https://snap.stanford.edu/data/egonets-Facebook.html]. It has 4,039 vertices and 88,234 edges. | ||
+ | * [http://theory.cpe.ku.ac.th/~jittat/courses/01204212/tasks/graph1/twitter.in twitter.in] -- This is a graph from twitter. It is a directed graph. This graph is from [https://snap.stanford.edu/data/egonets-Twitter.html]. It has 81,306 vertices and 1,768,149 edges. | ||
+ | |||
+ | '''The graph format:''' | ||
+ | |||
+ | * First line: two integers ''n'' and ''m'', where ''n'' is the number of vertices and ''m'' is the number of edges | ||
+ | * Next ''m'' lines: each line contains two integers ''u'' and ''v'' (ranging from 0 to n-1). In an undirected graph, this means that there is an edge between ''u'' and ''v''. In a directed graph, this means that there is an edge from ''u'' to ''v''. | ||
+ | |||
+ | == Tasks 1 == | ||
+ | For an undirected graph, find the vertices with the highest degree. For a directed graph (twitter), find vertices with the highest in-degree and vertices with highest out-degree. | ||
+ | |||
+ | == Tasks 2 == | ||
+ | Consider vertex 0 and vertex ''n''-1. Find the length of the shortest path from vertex 0 to vertex ''n''-1. | ||
+ | |||
+ | == Tasks 3 == | ||
+ | In twitter graph, find out how many vertices that are reachable from vertex 0 but vertex 0 cannot be reachable from them. | ||
== Code == | == Code == | ||
แถว 40: | แถว 59: | ||
for(int i=0; i<m; i++) { | for(int i=0; i<m; i++) { | ||
items = reader.readLine().split(" "); | items = reader.readLine().split(" "); | ||
− | int u = Integer.parseInt(items[0]) | + | int u = Integer.parseInt(items[0]); |
− | int v = Integer.parseInt(items[1]) | + | int v = Integer.parseInt(items[1]); |
adjList[u].add(v); | adjList[u].add(v); | ||
แถว 50: | แถว 69: | ||
} | } | ||
} | } | ||
+ | </syntaxhighlight> | ||
+ | |||
+ | === findLevels === | ||
+ | <syntaxhighlight lang="java"> | ||
+ | void findLevels(int s) { | ||
+ | List<Integer> nextLevel = new ArrayList<Integer>(); | ||
+ | levels = new int[n]; | ||
+ | for(int u=0; u<n; u++) { | ||
+ | levels[u] = -1; | ||
+ | } | ||
+ | levels[s] = 0; | ||
+ | nextLevel.add(s); | ||
+ | |||
+ | while(! nextLevel.isEmpty()) { | ||
+ | List<Integer> currentLevel = nextLevel; | ||
+ | nextLevel = new ArrayList<Integer>(); | ||
+ | |||
+ | for(int u : currentLevel) { | ||
+ | for(int v : adjList[u]) { | ||
+ | if(levels[v] == -1) { | ||
+ | levels[v] = levels[u] + 1; | ||
+ | nextLevel.add(v); | ||
+ | } | ||
+ | } | ||
+ | } | ||
+ | } | ||
+ | } | ||
</syntaxhighlight> | </syntaxhighlight> |
รุ่นแก้ไขปัจจุบันเมื่อ 06:40, 1 ธันวาคม 2559
- This part of 01204212
In this task you will work with graphs from real social networks.
- facebook.in -- This is a graph from facebook. It is an undirected graph. The graph is from [1]. It has 4,039 vertices and 88,234 edges.
- twitter.in -- This is a graph from twitter. It is a directed graph. This graph is from [2]. It has 81,306 vertices and 1,768,149 edges.
The graph format:
- First line: two integers n and m, where n is the number of vertices and m is the number of edges
- Next m lines: each line contains two integers u and v (ranging from 0 to n-1). In an undirected graph, this means that there is an edge between u and v. In a directed graph, this means that there is an edge from u to v.
เนื้อหา
Tasks 1
For an undirected graph, find the vertices with the highest degree. For a directed graph (twitter), find vertices with the highest in-degree and vertices with highest out-degree.
Tasks 2
Consider vertex 0 and vertex n-1. Find the length of the shortest path from vertex 0 to vertex n-1.
Tasks 3
In twitter graph, find out how many vertices that are reachable from vertex 0 but vertex 0 cannot be reachable from them.
Code
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;
public class Main {
public static void main(String[] args) {
Main main = new Main();
main.process();
}
int n,m;
List<Integer> [] adjList;
void process() {
readInput();
}
private void readInput() {
BufferedReader reader = new BufferedReader(
new InputStreamReader(System.in) );
try {
String[] items = reader.readLine().split(" ");
n = Integer.parseInt(items[0]);
m = Integer.parseInt(items[1]);
adjList = (List<Integer>[])(new List[n]);
for(int i=0; i<n; i++) {
adjList[i] = new ArrayList<Integer>();
}
for(int i=0; i<m; i++) {
items = reader.readLine().split(" ");
int u = Integer.parseInt(items[0]);
int v = Integer.parseInt(items[1]);
adjList[u].add(v);
adjList[v].add(u);
}
} catch(Exception e) {
}
}
}
findLevels
void findLevels(int s) {
List<Integer> nextLevel = new ArrayList<Integer>();
levels = new int[n];
for(int u=0; u<n; u++) {
levels[u] = -1;
}
levels[s] = 0;
nextLevel.add(s);
while(! nextLevel.isEmpty()) {
List<Integer> currentLevel = nextLevel;
nextLevel = new ArrayList<Integer>();
for(int u : currentLevel) {
for(int v : adjList[u]) {
if(levels[v] == -1) {
levels[v] = levels[u] + 1;
nextLevel.add(v);
}
}
}
}
}