Usaco2008
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Mirrored from [1]. Source from the old USACO website is currently unavailable.
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OPEN08
Source for test cases and analysis: [2]
Problem 1: The Ultimate Battle [Christos Tzamos, 2007]
Bessie and Canmuu are battling each other on a rectagular W x H (1 <= W <= 5,000; 1 <= H <= 5,000) field. Bessie is initially positioned at coordinates (x1,y1) (1 <= x1 <= W; 1 <= y1 <= H); Canmuu is positioned in different row and column at coordinates (x2,y2) (1 <= x2 <= W; 1 <= y2 <= H; x1 != x2; y1 != y2). The Ultimate Battle's winner is the first player who plasters the other with a pie in the face. While both players can see each other at all times, they can only plaster their opponent with a pie in the face when the opponent passes through (or stops on) the row or column occupied by the pie-thrower. Bessie starts first and they alternate turns. During each turn, a player can move as many steps in any one of the four rectilinear directions (up, down, left, right) as they wish -- without exceeding the limits of the yard, of course. Bessie asks for your help to beat Canmuu. Write a program to tell her where to move for each of her turns. This task is "interactive". Your program must first read six integers from the input file and then interact with the grader as follows: At each of Bessie's turns, the program calculates and outputs the Bessie's new location. The new location must be a valid move, i.e., Bessie's new coordinate must differ from old one either in the x or y coordinate but not both. If she moves through one of Canmuu's x or y coordinates, the game terminates automatically with a moose victory (and a "wrong answer" for you). If Canmuu cannot make a move without losing, the grader will terminate your program automatically and award Bessie the victory. Otherwise, your program should read in Canmuu's move in two integers, the new coordinates of the methodical moose. You may assume that Bessie will always start in a situation where a victory is possible. You may also assume that Canmuu is no fool. NOTE: Read the six integers from file pieface.in; read Canmuu's moves from the standard input (i.e., console). ---------------- Reactive Programs ---------------------- In order to ensure that your program's output is not buffered inside your program; you must 'flush' your output. If you're using stdio.h, include the line setbuf(stdout, 0); near the top of your program. If you're using C++ style I/O, flush each output line like this: cout << line << "\n" << flush; For Pascal, add the following statement after each writeln statement: flush(stdout); For Java, add the following after each output statement: System.out.flush(); If your program 'times out' after you wrote a reply, it probably is not properly flushing the output. ---------------- JAVA USERS ---------------------- Here is (we hope) the skeleton of input/output statements you will need: import java.io.*; import java.util.*; public class pieface { public static void main(String[] args) throws IOException { BufferedReader in = new BufferedReader(new InputStreamReader(System.in)); /* write ... */ System.out.println(...); System.out.flush(); /* read a reply */ response = in.readLine(); ... PROBLEM NAME: pieface INPUT FORMAT: * Line 1: Six space-separated integers: W, H, x1, y1, x2, and y2 SAMPLE INPUT (file pieface.in): 3 3 1 1 2 3 OUTPUT FORMAT: * Line All: Each output line contains a pair of space-separated integers that represent Bessie's new location. SAMPLE OUTPUT (file pieface.out): Do not use the file 'pieface.out'. See below for sample interactions. OUTPUT DETAILS: Here is a possible winning interaction: > 1 2 Bessie moves up by 1 to 1,2 < 3 3 Canmuu moves to 1 to the right to 3,3 > 2 2 Bessie moves to 2,2 by going one to the right At which point Canmuu could no longer make a move without getting a pie in the face. 3 . C . . C . . . C . . C 2 . . . => B . . => B . . => . B . => Canmuu must pass Bessie's row 1 B . . . . . . . . . . . or column on his next move 1 2 3 1 2 3 1 2 3 1 2 3
Problem 2: Crisis on the Farm [Thomas Williamson, 2004]
Farmer John and his herd of exotic dancing bovines have been practicing for his new moosical, "The Street Cow Named Desire". At one point in the middle of rehearsal, his cows are stacked on top of each other in N (1 <= N <= 1,000) sets of 30, one cow standing on the back of the other (they are quite amazing cows). Thus, the pasture is dotted with both these stacks of 30 cows and also, in separate locations, M (1 <= M <= 1,000) haystacks. Below is a sample of one way they might be laid out: 8 ......... 7 ....CH.H. C = stack of 30 cows 6 ......... 5 ......... H = haystack 4 ..C.HH... 3 ......... 2 .....C.HH 1 ......... 123456789 As the musical's conductor, Farmer John has four whistles with various tones. One whistle commands the cow at the bottom of each stack to move (along with all the stacked cows) one unit north, another indicates a move to the south, one indicates a move to the east, and a fourth to order a move to the west. Any time the stack of cows enters a grid location with a haystack, the cow on the top of the stack (even if the stack has height one) will jump onto the haystack while the remaining cows move into the same location as the haystack. Thus, if the bottom cow encounters 30 haystacks (perhaps different haystacks, perhaps not), the stack of 30 cows is exhausted with all the cows standing on top of haystacks (or standing on cows on haystacks). The sturdy haystacks can each support an unlimited number of cows. Farmer John glances across his pasture to Farmer Don's milking facility to see, to his horror, a huge milk tank exploding and unleashing a giant tidal wave of milk making its way toward the performing cows! Since any cows on a haystack are safe, FJ must now do what he can to save the lives of as many cows as possible using what has turned from a simple dance routine into a lifesaving technique. Given the number of times K (1 <= K <= 30) farmer John can blow a whistle until the wave of milk crashes over the pasture and also the X_i, Y_i positions (1 <= X_i <= 1,000; 1 <= Y_i <= 1,000) of the N stacks of cows and M haystacks (none of which currently has any cows on it), report the greatest number of cows that can be saved and find a sequence of whistle blows that does the job. The sequence should be reported in terms of the four directions, 'E' for east, 'N' for north, 'W' for west, 'S' for south. Among all such sequences, farmer John wants the lexicographically least. Initial locations of cows and haystacks will not share the same coordinates in the input file. Cows can be moved to any location, including ones outside the pasture. PROBLEM NAME: crisis INPUT FORMAT: * Line 1: Three space-separated integers: N, M, and K * Lines 2..N+1: Line i+1 describes the X,Y location of a stack of 30 cows using two space-separated integers: X_i and Y_i * Lines N+2..N+M+1: Line i+N+1 describes the X,Y location of a haystack using two space-separated integers: X_i and Y_i SAMPLE INPUT (file crisis.in): 3 6 3 3 4 6 2 5 7 8 2 9 2 6 4 5 4 6 7 8 7 OUTPUT FORMAT: * Line 1: A single integer that is the most number of cows that can be saved. * Line 2: K characters, the lexicographically least sequence of commands FJ should issue to maximize the number of cows saved. SAMPLE OUTPUT (file crisis.out): 6 EEE OUTPUT DETAILS: Use the 'east' whistle three times, at which point the milk floods the area. Each haystack ends up saving 1 cow.
Problem 3: Cow Neighborhoods [Richard Ho, 2006]
Those Who Know About Cows are aware of the way cows group into "Cow Neighborhoods". They have observed Farmer John's N (1 <= N <= 100,000) cows (conveniently numbered 1..N) as they graze, each at her own unique integer rectilinear coordinate, on a pasture whose X and Y coordinates are in the range 1..1,000,000,000. Two cows are neighbors if at least one of two criteria is met: 1) If the cows are no further than some integer Manhattan distance C (1 <= C <= 1,000,000,000) apart, they are neighbors. [Manhattan distance is calculated as d = |x1-x2| + |y1-y2|.] 2) If cow A is a neighbor of cow Z and cow B is a neighbor of cow Z, then cow A is a neighbor of cow B (the "transitive closure of neighbors"). Given the locations of the cows and the distance C, determine the the number of neighborhoods and the number of cows in the largest neighborhood. By way of example, consider the pasture below. When C = 4, this pasture has four neighborhoods: a big one on the left, two neighborhoods of size 1 (the lonesome cows), and a huge neighborhood on the right with 60 different cows. .....................................*................. ....*...*..*.......................***................. ......*...........................****................. ..*....*..*.......................*...*.******.*.*..... ........................*.............***...***...*.... *..*..*...*..........................*..*...*..*...*... .....................................*..*...*..*....... .....................................*..*...*..*....... ...*................*.................................. .*..*............................*.*.*.*.*.*.*.*.*.*.*. .*.....*..........................*.*.*.*.*.*.*.*.*.*.* ....*.................................................. The input file describes cow locations by integer X,Y coordinates, where the lower left corner is (1,1) and cows close to that corner appear at both (2,2) and (5,1) in the example above. For a given pasture, determine both the number of cow neighborhoods and the number of cows resident in the largest cow neighborhood. The above picture is sample test case 2, which will be evaluated for you upon submission. Partial feedback for some test cases will be provided on the first 10 submissions. Time Limit: 2 seconds Memory Limit: 32MB PROBLEM NAME: nabor INPUT FORMAT: * Line 1: Two space-separated integers: N and C * Lines 2..N+1: Line i+1 describes cow i's location with two space-separated integers: X_i and Y_i SAMPLE INPUT (file nabor.in): 4 2 1 1 3 3 2 2 10 10 OUTPUT FORMAT: * Line 1: A single line with a two space-separated integers: the number of cow neighborhoods and the size of the largest cow neighborhood. SAMPLE OUTPUT (file nabor.out): 2 3 OUTPUT DETAILS: There are 2 neighborhoods, one formed by the first three cows and the other being the last cow. The largest neighborhood therefore has size 3.